![File:Dihedral group of order 8; Cayley table (element orders 1,2,2,4,4,2,2,2); subgroup of S4 (left).svg - Wikimedia Commons File:Dihedral group of order 8; Cayley table (element orders 1,2,2,4,4,2,2,2); subgroup of S4 (left).svg - Wikimedia Commons](https://upload.wikimedia.org/wikipedia/commons/thumb/d/d3/Dihedral_group_of_order_8%3B_Cayley_table_%28element_orders_1%2C2%2C2%2C4%2C4%2C2%2C2%2C2%29%3B_subgroup_of_S4_%28left%29.svg/1200px-Dihedral_group_of_order_8%3B_Cayley_table_%28element_orders_1%2C2%2C2%2C4%2C4%2C2%2C2%2C2%29%3B_subgroup_of_S4_%28left%29.svg.png)
File:Dihedral group of order 8; Cayley table (element orders 1,2,2,4,4,2,2,2); subgroup of S4 (left).svg - Wikimedia Commons
![I've worked out what the Cayley tables are and have therefore said that identity 1 from G is mapped to identity [0] in H and -i is mapped to [3] but 'm I've worked out what the Cayley tables are and have therefore said that identity 1 from G is mapped to identity [0] in H and -i is mapped to [3] but 'm](https://preview.redd.it/fv7fc6xqfds91.png?width=404&format=png&auto=webp&s=3a350c8b13e79dc766d93db970487f8b6af8f109)
I've worked out what the Cayley tables are and have therefore said that identity 1 from G is mapped to identity [0] in H and -i is mapped to [3] but 'm
![Cayley table for T (primary tumor) graded according to scale 0-7 (8... | Download Scientific Diagram Cayley table for T (primary tumor) graded according to scale 0-7 (8... | Download Scientific Diagram](https://www.researchgate.net/publication/233948340/figure/fig4/AS:667777216024579@1536221903122/Cayley-table-for-T-primary-tumor-graded-according-to-scale-0-7-8-grades.png)
Cayley table for T (primary tumor) graded according to scale 0-7 (8... | Download Scientific Diagram
![SOLVED: SL0 13) Let G = D6 with Cayley table below and H = e, r2, r4, a normal subgroup of G | | e | r | r^2 | r^3 SOLVED: SL0 13) Let G = D6 with Cayley table below and H = e, r2, r4, a normal subgroup of G | | e | r | r^2 | r^3](https://cdn.numerade.com/ask_images/7832a6493a8d4665b27857b3935dc4a3.jpg)
SOLVED: SL0 13) Let G = D6 with Cayley table below and H = e, r2, r4, a normal subgroup of G | | e | r | r^2 | r^3
![Table 4 from On the structure and zero divisors of the Cayley-Dickson sedenion algebra | Semantic Scholar Table 4 from On the structure and zero divisors of the Cayley-Dickson sedenion algebra | Semantic Scholar](https://d3i71xaburhd42.cloudfront.net/88fa65ac678d3ad8a2636b69571391328e96aed0/10-Table4-1.png)